Archive for August, 2009

Need to take a hiatus

Friday, August 14th, 2009

I'm needing to take a couple of weeks of hiatus from the blog. I shall return! SHARETHIS.addEntry({ title: "Need to take a hiatus", url: "http://wildaboutmath.com/2009/08/14/need-to-take-a-hiatus/" });

MMM #37: Prize 4

Monday, August 10th, 2009

Alan provided a very different solution from the others and provided a Matlab program for his solution: I wrote a solution in MATLAB - I think its only uses standard mathematical functions, but I'll clarify if needed. inputs/outputs (x,y): as defined in your post z: integer value at coordinate (x,y) intermediate variables: r0: which square 'ring' ...

MMM #37: Prizes 2 and 3

Thursday, August 6th, 2009

Today I'm announcing two more prizes for MMM #37. Here is IB Yea's solution: The problem is to find the algorithm for the coordinate and number for the spiral that goes like the following: 25 24 23 22 21 10 09 08 07 20 11 02 01 06 19 12 03 04 05 18 13 14 15 ...

MMM #37: Prize #1

Tuesday, August 4th, 2009

I'm going to give a number of $10 prizes for MMM #37. Here's the first to Alec Cooper for his very elegant solution. I paid Alec to look through all the submissions to determine which were correct. Most were. I'll be giving a prize to everyone who turned in a ...

MMM #38: square or no square?

Monday, August 3rd, 2009

Results of MMM #37 should be out in the next couple of days. Here's MMM #38: Prove or disprove: The product of any four consecutive integers is always one less than a perfect square. Don't assume the integers are all positive. SHARETHIS.addEntry({ title: "MMM #38: square or no square?", url: "http://wildaboutmath.com/2009/08/03/mmm-38-square-or-no-square/" });

Still working on reviewing MMM #37

Sunday, August 2nd, 2009

I got submissions from eight people for this latest problem. Yes, this problem was tougher than most so I'm delighted to have gotten so many entries. I recently started work on a big software development project on a very tight schedule so I've not had the time to check each ...